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4h^2+24h+7=0
a = 4; b = 24; c = +7;
Δ = b2-4ac
Δ = 242-4·4·7
Δ = 464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{464}=\sqrt{16*29}=\sqrt{16}*\sqrt{29}=4\sqrt{29}$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{29}}{2*4}=\frac{-24-4\sqrt{29}}{8} $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{29}}{2*4}=\frac{-24+4\sqrt{29}}{8} $
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